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3 years ago

(WILL MARK BRAINLIEST AND THANK YOU!!)

Mathematics

1 answer:

Oduvanchick [21]3 years ago

5 0

Answer:

$-5m(-2m^6+4m^4+m-9)\\\\10m^7-20m^5-5m^2+45m$

Standard form is in the order of descending degrees.

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Simon bought 5 boxes of cereal c and 2 gallons of nonfat milk m for $20.08. Terri bought 3 of the same boxes of cereal b and 3 g

Effectus [21]

Answer:

2.50$

Step-by-step explanation:

8 0

3 years ago

Can someone help with this?

MAXImum [283]

I belive it is the second option!

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3 years ago

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Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

Given:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

Coordinates of the point A':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point A(-2,3), we get;

$(-2,3)\rightarrow (-2,-3)$

Thus, the coordinates of the point A' is (-2,-3)

Coordinates of the point B':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

$(0,3)\rightarrow (0,-3)$

Thus, the coordinates of the point B' is (0,-3)

Coordinates of the point C':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0

3 years ago

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below:

$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

Now putting 1 in $x$ gives us the limit:

$\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5$

So the answer is 5

3 0

3 years ago

Which statement correctly describes the relationship between the graph of f(x)g(x) and g(x)=f(x−7)?

Lelu [443]

G(x) would have to be -->7 units.
The relationship between f(x) and s(x) where s(x)=af(x-b)+z is that g(x) is f(x) stretched by the reciprocal of a, b is the liar (all x values go up if b goes down and visa versa), and it moves up z units.

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3 years ago

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