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3 years ago

Can someone help me with some questions please!

Mathematics

1 answer:

galben [10]3 years ago

4 0

Answer:

i would say around 61.54%

Step-by-step explanation:

maybe simplify it

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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3 years ago

What is √117 simplified

kenny6666 [7]

Answer:

10.82

Step-by-step explanation:

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3 years ago

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The results of a poll show that the percent of people who want a new restaurant is in the interval (62%, 88%). There are 109,482

uranmaximum [27]

Answer:

(67879,96344)

Step-by-step explanation:

I took the test

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3 years ago

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Please help I am doing a test right now

sineoko [7]

Answer:

yeet

Step-by-step explanayeettion:

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3 years ago

Find a ·<br> b. |a| = 80, |b| = 50, the angle between a and b is 3π/4.

mart [117]

Answer:

$a\cdot b=-2000\sqrt{2}$

Step-by-step explanation:

Given information: |a| = 80, |b| = 50, the angle between a and b is 3π/4.

We need to find the dot product a · b.

The formula of dot product is

$a\cdot b=|a||b|\cos \theta$

where, θ is the angle between a and b.

Substitute the given values in the above formula.

$a\cdot b=(80)(50)\cos (\frac{3\pi}{4})$

$a\cdot b=4000\cos (\pi-\frac{\pi}{4})$

$a\cdot b=-4000\cos (\frac{\pi}{4})$ $[\because \cos (\pi-\theta)=-\cos \theta]$

$a\cdot b=-4000\frac{1}{\sqrt{2}}$

$a\cdot b=-\frac{4000}{\sqrt{2}}$

Rationalize the above equation.

$a\cdot b=-\frac{4000}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}$

$a\cdot b=-\frac{4000\sqrt{2}}{2}$

$a\cdot b=-2000\sqrt{2}$

Therefore, the value of a · b is $a\cdot b=-2000\sqrt{2}$ .

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3 years ago

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