Question

7 \sqrt{160} " alt="4 \sqrt{40} + 7 \sqrt{160} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

36$\sqrt{10}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals in the expression

$\sqrt{40}$

= $\sqrt{4(10)}$

= $\sqrt{4}$ × $\sqrt{10}$ = 2$\sqrt{10}$

$\sqrt{160}$

= $\sqrt{16(10)}$

= $\sqrt{16}$ × $\sqrt{10}$ = 4$\sqrt{10}$

Thus

4$\sqrt{40}$ + 7$\sqrt{160}$

= 4 × 2$\sqrt{10}$ + 7 × 4$\sqrt{10}$

= 8$\sqrt{10}$ + 28$\sqrt{10}$

= 36$\sqrt{10}$

Answer 2

Answer:

Step-by-step explanation:

4$4\sqrt{40} + 7 \sqrt{160} = 4\sqrt{2*2*2*5} + 7\sqrt{4*4*5*2}\\ = 4*2\sqrt{10} + 7*4\sqrt{10}\\ = 8\sqrt{10} + 28\sqrt{10}$

= (8 + 28)√10

= 36√10