2 3/4 + 1 5/8 + 1 5/8 =
2 + 1 + 1 = 4 (add the whole numbers)
3/4 + 5/8 + 5/8 = 6/8 + 5/8 + 5/8 = 16/8 = 2 (add the fractions)
4 + 2 = 6 total lbs

5.40 for 6 lbs = 5.40/6 = 0.90 (so the apples cost 90 cents per lb)

7 0

3 years ago

Suppose that 45% of people have dogs. If two people are randomly chosen, what is the probability that they both have a dog

mylen [45]

Answer:

$P(Dogs) = 0.2025$

Step-by-step explanation:

Given

$Proportion, p = 45\%$

Required

Probability of two people having dog

First, we have to convert the given parameter to decimal

$p = \frac{45}{100}$

$p = 0.45$

Let P(Dogs) represent the required probability;

This is calculated as thus;

P(Dogs) = Probability of first person having a dog * Probability of second person having a dog

$P(Dogs) = p * p$

$P(Dogs) = 0.45 * 0.45$

$P(Dogs) = 0.45^2$

$P(Dogs) = 0.2025$

Hence, the probability of 2 people having a dog is  $P(Dogs) = 0.2025$ 

4 0

3 years ago