X + 10 = 62
x = 52
The number you started with is 52.
The volume of the region R bounded by the x-axis is: 
<h3>What is the volume of the solid (R) on the X-axis?</h3>
If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
From the given graph:
The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

here:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:

y = 4x
Now, our region bounded by the three lines are:
Similarly, the change in polar coordinates is:
where;
- x² + y² = r² and dA = rdrdθ
Therefore;
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:


Learn more about the determining the volume of solids bounded by region R here:
brainly.com/question/14393123
#SPJ1
Answer:
3rd box
Step-by-step explanation:
BRAINLIEST PLEASE
Answer: (A) 352 π units^2
Explanation in image.
Knowledge point:
Geometry - cylinder area formula
Step by step solution :<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span><span> (((3•(x2))•(y4))3)
4•——————————————————
((2x3•(y5))4)
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span><span> ((3x2 • (y4))3)
4 • ———————————————
24x12y20
</span><span> Step 3 :</span><span> 33x6y12
Simplify ————————
24x12y20
</span></span>Dividing exponential expressions :
<span> 3.1 </span> <span> x6</span> divided by <span>x12 = x(6 - 12) = x(-6) = 1/<span>x6</span></span>
Dividing exponential expressions :
<span> 3.2 </span> <span> y12</span> divided by <span>y20 = y(12 - 20) = y(-8) = 1/<span>y8</span></span>
<span>Equation at the end of step 3 :</span><span> 27
4 • ——————
16x6y8
</span><span>Step 4 :</span>Final result :<span> 27
—————
4x6y<span>8</span></span>