A particle, initially 15 m from the origin and travelling at -2 ms), accelerates at a constant rate and ends up -20 m from the o

Question

igor_vitrenko [27]

3 years ago

11

A particle, initially 15 m from the origin and travelling at -2 ms), accelerates at a constant rate and ends up -20 m from the o

rigin and travelling at -5 ms?
What is its acceleration?

Mathematics

1 answer:

tigry1 [53] · Answer 1 · 2022-12-19T22:38:08+03:00

the general equation for velocity in terms of acceleration and displacement is: v² = v₀² + 2ax.

Solve for a: a = (v² - v₀²)/(2x).

You are given v₀ and v, and x is easy to calculate since you are given its initial and final values. The rest is just arithmetic.

(note also: SI expressions have a required space between the coefficient and the unit symbol. Thus you should have things such as “15 m” and “-2 m·sˉ¹” instead of “15m” and “-2m·sˉ¹”.)