Answer:
Step-by-step explanation:
For the points lol
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
Answer:
y=124°
x=67°
Step-by-step explanation:
For the triangle on the right
180-74-50=56°
then y= 180-56=124°
For the triangle on the middle (that small triangle)
180-85(Head opposite angles)-50=45°
So
x=180-45-68=67°
9514 1404 393
Answer:
d. m∠Q = 75 degrees
Step-by-step explanation:
The sum of the angles in a triangle is 180°. This triangle is marked to show it is an isosceles triangle, so the two base angles have the same measure.
∠P +∠Q +∠R = 180°
x° +(2x +15)° +(2x +15)° = 180°
5x = 150 . . . . . . . . . . . . . . . . . . . divide by °, subtract 30
x = 30 . . . . . . . . . . . . . . . . divide by 5
m∠Q = (2x +15)° = (2(30) +15)°
m∠Q = 75°
