By conservation of linear amount of movement we have:
m1v1i + m2v2i = m1v1f + m2v2f
Where,
v1i = v2i = 0 (assuming initial rest)
m1v1f + m2v2f = 0
Substituting the values:
m1 (-3) + (1) (150) = 0
Clearing m1:
m1 = (- (1) * (150)) / (- 3)
m1 = 50 Kg
answer:
his mass is 50 Kg
Answer:
C
Step-by-step explanation:
It is between 3.1 and 3.17 or 3.2 if you want it by hundredths.
This is because 3.16 is 3.1600000 and many more zeros but 3.16227766 is slightly over that so it would be between 3.1 and 3.17.
Answer:
By the Central Limit Theorem, the average value for all of the sample means is 14.
Step-by-step explanation:
We use the central limit theorem to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, the sample means of size n can be approximated to a normal distribution with mean and standard deviation, which is also called standard error 
If the population mean is μ = 14, then what is the average value for all of the sample means?
By the Central Limit Theorem, the average value for all of the sample means is 14.
Answer:
x = -5/7
Step-by-step explanation:
8/(x+3)=1/(x+1)
Using cross products
8*(x+1) = 1*(x+3)
Distribute
8x+8 = x+3
Subtract x from each side
8x-x +8 = x+3-x
7x +8 =3
Subtract 8 from each side
7x+8-8 = 3-8
7x = -5
Divide by 7
7x/7 = -5/7
x = -5/7
