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3 years ago

A farmer sells an average of 15 bushels of corn

Mathematics

2 answers:

S_A_V [24]3 years ago

8 0

Answer:

he goes from 15 to 90 ears of corn in 6 days

Step-by-step explanation:

15*6=90

yawa3891 [41]3 years ago

5 0

Is this a math tb question? if so reply so i can help and tell you the 100% correct answer.

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Please help -2x++8-6=-32

arlik [135]

Answer:

x = 17

Step-by-step explanation:

-2x+8-6=-32

lets isolate the x variable:

-2x=-32-8+6

-2x = -34

x= -34/-2

x= 34/2

x= 17

3 0

4 years ago

Explain what a variable is

AleksAgata [21]

A variable is a letter that replaces an unknown number.

7 0

3 years ago

Determine if the statement is true or false. If a linear system has the same number of equations and variables, then it must hav

lutik1710 [3]

Answer:

False

Step-by-step explanation:

Consider the equations with the same number of equations and variables as shown below,

$x_{1} + x_{2} = 0\\x_{1} + x_{2} = 1$

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.

$x_{1} + x_{2} = 1\\2x_{1} + 2x_{2} = 2$

This equation has infinitely many possible solutions.

Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.

5 0

3 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

PLEASEEE

zzz [600]

Answer:

13.4

Step-by-step explanation:

AB =2DC

So, DC=AB/2

Now, AB/AC=DE/DC

AB/28=13/(AB/2)

AB²=13×28×2

AB=√728

AB=26.98

now, DC=AB/2

=13.4

6 0

3 years ago