It goes in evenly 2 times
Answer:
23
Step-by-step explanation:
i think
Answer:
Two
Step-by-step explanation:
x² + 4 = 4x + 1
x² - 4x + 3 = 0
x² - 3x - x + 3 = 0
x(x - 3) - (x - 3) = 0
(x - 3)(x - 1) = 0
x = 1, 3
y = 4(1) + 1 = 5
y = 4(3) + 1 = 13
Two solutions: (1,5) (3,13)
Answer:
Since b^2 -4ac = 256 we have 2 real distinct root roots
Step-by-step explanation:
4x^2+12x=7
We need to subtract 7 to get it in the proper form
4x^2+12x-7=7-7
4x^2+12x-7=0
The discriminant is b^2 -4ac
when the equation is ax^2 +bx+c
so a =4 b=12 and c=-7
(12)^2 - 4(4)(-7)
144 +112
256
If b^2 -4ac > 0 we have 2 real distinct roots
If b^2 -4ac = 0 we have one real root
If b^2 -4ac < 0 we have two complex root
Since b^2 -4ac = 256 we have 2 real distinct root roots
