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Marina86 [1]
3 years ago
15

PLS HELP ME W/ #8 ASAP

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

x=2

TU:4(2)-1=7

UB: 3

TB: 10

Step-by-step explanation:

4x-1+2x-1=5x

6x-2=5x

6x=5x+2

subtract 5x from both sides

x=2

TU: (4x-1)

4(2)-1

8-1

7

TU:4(2)-1=7

UB: (2x-1)

2(2)-1

4-1

3

UB: 3

TB: 5(2)

TB: 10

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We have:

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Use

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x^2-2(x)(2)+y^2-2(y)(3)=-8\qquad\text{add}\ 2^2\ \text{and}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2-2(x)(2)+2^2}_{(*)}+\underbrace{y^2-2(y)(3)+3^2}_{(*)}=2^2+3^2-8\\\\(x-2)^2+(y-3)^2=4+9-8\\\\(x-2)^2+(y-3)^2=5\\\\(x-2)^2+(y-3)^2=(\sqrt5)^2\\\\Answer:\\\\\boxed{center:(2,\ 3)}\\\\\boxed{radius:r=\sqrt5}

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