We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)
To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c
Now we write this as a sum in one binomial and a difference in the other:
(5b⁸+8c)(5b⁸-8c)
-230 because it is farther away from 0
For
ax^2+bx+c=
and a=1
b/2 squared=c makes a perfect square
b=16
16/2=8
8^2=64
the value of c should be 64
factored form
(x+8)^2
The GCF is 5 so the new expression would be: 5(x+2)
Answer:
24.
Step-by-step explanation:
Substitute each instance of x with a 3.
That leaves us with 3^2 + 3x - 5 + 3^2 - 3x + 11.
Combine like terms.
2(3^2) + 6.
Simplify.
2(9) + 6
18 + 6
24.
