1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex Ar [27]
3 years ago
6

Jennifer painted 168 pots in 14 days. How many pots can she paint in 30 days?

Mathematics
2 answers:
svlad2 [7]3 years ago
6 0
168÷14=12
12×30=360 pots
Vaselesa [24]3 years ago
4 0
The answer would be 360 because if you divide 168 by 14, you'll get the number of pots made each day. And so if 168 pots are made in 14 days, just multiply that by two to get 336 pots made in 28 days. Now, just multiply the number of pots made each day(12) by 2 since there are two remaining days left to get 24. Finally, you add 24 to 336 to get your solution: 360.

168*2
336 pots made in 28 days

12*2
24 pots made in the remaining 2 days left

336+24
360 pots are made in a total of 30 days

You might be interested in
Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

6 0
3 years ago
Which situation is best described by the graph shown?
kramer
Where’s the graph???
8 0
3 years ago
A certain flight arrives on time 80 percent of the time. Suppose 132 flights are randomly selected. Use the normal approximation
kondaur [170]
D because 118 and 120 is even numbers
3 0
3 years ago
4. Give the sum of the prime factors of 10.
andreyandreev [35.5K]
4+6 and 2+8 I’m not sure it is
3 0
2 years ago
Which set of values could be the side lengths of a 30-60-90 triangle?
PilotLPTM [1.2K]

The correct answer is option B which is the set of values that could be the side lengths of a 30-60-90 triangle are (6,6√3, 12).

<h3>What is the right-angled triangle?</h3>

A triangle has three angles of 30-60 and 90 degrees in which the two sides are perpendicular to each other.

The three sides of the triangle will be calculated by applying the Pythagorean theorem:-

The sum of the square sides will be equal to the square of the third side.

For sides  (6,6√3, 12)

12² = 6² + (6√3)²

144 = 36 + (36 x 3)

144 = 36 + 108

144 = 144

Therefore the correct answer is option B which is the set of values that could be the side lengths of a 30-60-90 triangle (6,6√3, 12).

To know more about right angle follow

brainly.com/question/64787

#SPJ1

5 0
2 years ago
Other questions:
  • Y=1/4x+1 what is the graph points
    11·2 answers
  • What is the density of a brick
    13·1 answer
  • -2 1/3 - (-5) =??????
    7·2 answers
  • What is the greatest value of the data represented by the box plot?
    15·2 answers
  • anna, charlie and michael are hungry at the fair. they buy a candy floss, a hot dog, and a gourmet burger, respectively. they me
    14·1 answer
  • What is 9962 divided by 41
    5·1 answer
  • What is the equation of a line that is perpendicular to y=4x-5 and passes through (-4,6)
    6·1 answer
  • Linda Davis agreed to lend money to Alex Luciano at a special interest rate of ​9% per​ year, on the condition that he borrow en
    7·1 answer
  • Calculate 50% of 200
    12·2 answers
  • Michael has interviewed for two jobs. He feels that he has a 50% chance of getting an offer on Job A and a 60% chance of getting
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!