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3 years ago

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Narine is solving the equation = 6 for q. Her work is shown. = 6 = 62 3q = A q = B What are the correct values for A and B? A =

6 B = 2 A = 9 B = 3 A = 12 B = 4 A = 36 B = 12

1 answer:

stepladder [879]3 years ago

7 0

Question:

Narine is solving the equation $\sqrt{3q} = 6$ for q. her work is shown

$\sqrt{3q} = 6$

$\sqrt{3q}^{2} = 6^2$

$3q = A$

$q =B$

What are the correct values for A and B?

Answer:

$A = 36$ and $B = 12$

Step-by-step explanation:

Given the above set of expressions

Find A and B

Recall her step 2

$\sqrt{3q}^{2} = 6^2$

From laws of indices;

$\sqrt{a^2} = a$

So, the expression becomes

$3q = 6^2$

Also, from laws of indices;

${a^2} = a * a$

So, the expression becomes

$3q = 6 * 6$

$3q =36$

Given that $A = 3q$

This implies that $A = 36$

Recall that $3q =36$

Divide both sides by 3

$\frac{3q}{3} =\frac{36}{3}$

$q =\frac{36}{3}$

$q =12$

Given that $q =B$

This implies that $B = 12$

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yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

$sin^4(x) + cos^4(x)$

We can rewrite this as:

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Now we can add and subtract cos^2(x)*sin^2(x) to get:

$(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)$

We can complete squares to get:

$(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2$

and we know that:

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then:

$1 - 2*sin(x)^2*cos(x)^2$

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

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3 years ago

Use a translator or whatever, just don't know how to do it. Will give most helpful answer brainliest, with an explanation and an

bekas [8.4K]

The answer is -60. this is because the signs implemented in front of numbers give it a sort pattern .

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3 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

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3 years ago

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Step-by-step explanation:

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Compound interest formula

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a.

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Simple interest is $125

b

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Compound interest is $125

c. the result for both a and b are the same

d.

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e

. $A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385$

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

g.

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the simple interest is $600

h.

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the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

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