Question

Narine is solving the equation = 6 for q. Her work is shown. = 6 = 62 3q = A q = B What are the correct values for A and B? A = 6 B = 2 A = 9 B = 3 A = 12 B = 4 A = 36 B = 12

Answer 1

Question:

Narine is solving the equation $\sqrt{3q} = 6$ for q. her work is shown

$\sqrt{3q} = 6$

$\sqrt{3q}^{2} = 6^2$

$3q = A$

$q =B$

What are the correct values for A and B?

Answer:

$A = 36$ and $B = 12$

Step-by-step explanation:

Given the above set of expressions

Find A and B

Recall her step 2

$\sqrt{3q}^{2} = 6^2$

From laws of indices;

$\sqrt{a^2} = a$

So, the expression becomes

$3q = 6^2$

Also, from laws of indices;

${a^2} = a * a$

So, the expression becomes

$3q = 6 * 6$

$3q =36$

Given that $A = 3q$

This implies that $A = 36$

Recall that $3q =36$

Divide both sides by 3

$\frac{3q}{3} =\frac{36}{3}$

$q =\frac{36}{3}$

$q =12$

Given that $q =B$

This implies that $B = 12$