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yaroslaw [1]
3 years ago
15

Given that sec x - tan x=1÷4​

Mathematics
1 answer:
solniwko [45]3 years ago
5 0

Answer:Let =tan2

t

=

tan

⁡

x

2

, then cos=1−21+2

cos

⁡

x

=

1

−

t

2

1

+

t

2

and tan=21−2

tan

⁡

x

=

2

t

1

−

t

2

.

Now

1+21−2+21−2(1+)21−21+1−tan2

Step-by-step explanation:

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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



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Step-by-step explanation:

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