Question

Given the quantities a = 6.1 m, b = 4.1 s, c = 87 m/s, what is the value of the quantity d = a3/(cb2)?

Answer 1

It is given in the question that

$a = 6.1 m, b = 4.1 s, c = 87 m/s$

And the given expression is

$d = \frac{a^3}{cb^2}$

Substituting the values of a,b and c, we will get

$d = \frac{6.1^3}{87*4.1^2} = 0.1552m^2/s$

So with the given values of a,b and c, we will get

$d=0.1552m^2/s$