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Taya2010 [7]
4 years ago
12

Given the quantities a = 6.1 m, b = 4.1 s, c = 87 m/s, what is the value of the quantity d = a3/(cb2)?

Mathematics
1 answer:
creativ13 [48]4 years ago
4 0

It is given in the question that

a = 6.1 m, b = 4.1 s, c = 87 m/s

And the given expression is

d = \frac{a^3}{cb^2}

Substituting the values of a,b and c, we will get

d = \frac{6.1^3}{87*4.1^2} = 0.1552m^2/s

So with the given values of a,b and c, we will get

d=0.1552m^2/s

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