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skad [1K]
4 years ago
5

What is the 10th term of the geometric sequence 400, 200, 100...?

Mathematics
1 answer:
Vsevolod [243]4 years ago
4 0

ANSWER

a_ {10} = \frac{25}{32}

EXPLANATION

The given geometric sequence is

400, 200, 100...

The first term is

a_1=400

The common ratio is

r =  \frac{200}{400}  =  \frac{1}{2}

The nth term is

a_n=a_1( {r}^{n - 1} )

We substitute the known values to get;

a_n=400(  \frac{1}{2} )^{n - 1}

a_ {10} =400(  \frac{1}{2} )^{10 - 1}

a_ {10} =400(  \frac{1}{2} )^{9}

a_ {10} = \frac{25}{32}

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We have been given that the vertices of a triangle are A (5, 0), B (x, y) and C (25, 0). We are asked to find the area of the given triangle.

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|\frac{A_x(B_y-C_y)+B_x(C_y-A_y)+C_x(A_y-B_y)}{2}|

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