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Sauron [17]
3 years ago
5

Which answer is the most reasonable estimation? Mike is driving a total of 100 miles. He drove 23 miles before stopping at a gas

station. Then he drove 58 more miles before stopping for lunch. About how much farther does Mike have to drive? A. about 20 miles B. about 80 miles C. about 10 miles D. about 70 miles

Mathematics
2 answers:
Ber [7]3 years ago
5 0
23 rounds to 20.
58 rounds to 60.

You then take your rounded numbers, 60 + 20 = 80. So, Mike has driven ABOUT 80 miles so far. 

Now you take his estimated distance & subtract it from the 100. Your answer is 20. So, your answer is A) 20 miles.

To check your work, you could add 23 + 58 = 81. You then subtract 100 - 81 = 19. 19 rounds to 20, which is your answer.

I hope this helps & you understand ! (:
Margarita [4]3 years ago
4 0
The answer is A because if you subtract 100-23-58 you get 19 then you simplify it

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<img src="https://tex.z-dn.net/?f=25x%5E%7B3%7D%20-215x%5E%7B2%7D%20%2B280x" id="TexFormula1" title="25x^{3} -215x^{2} +280x" al
Firlakuza [10]

Answer:

5x(5x - 8)(x - 7)

Step-by-step explanation:

25x³ - 215x² + 280x =

= 5x(5x² - 43x + 56)

= 5x(5x - 8)(x - 7)

3 0
2 years ago
3/11% of a quantity is equal to what fraction of the quantity? please explain
AysviL [449]
....................................do you mean 3.11%  
8 0
3 years ago
Please help, thanks!<br><br> Factor completely<br><br> Sx²- 13x² + 15x²
Andru [333]

Answer:

x^2(S+2)

Step-by-step explanation:

7 0
3 years ago
NetSell, a the TV remote control supplier for Lumyn Electronics, has a weekly production cost of q TV remote controls that is gi
natali 33 [55]

Answer:

a.  \frac{dC(q)}{dq} = 0.000012q^2 -0.06q + 100

b. \frac{dR(q)}{dq}=-0.01q+200

c.

U'(2000)=-0.000012(2000)^2+0.05(2000)+100 = 152

U'(7000)=-0.000012(7000)^2+0.05(7000)+100 = -138

 

Step-by-step explanation:

a) The marginal cost function is given by the derivative of the total cost function, in this way the marginal cost function for this company is:

\frac{dC(q)}{dq} = \frac{dC(q)}{dq} (0.000004q^ 3 - 0.03q ^ 2 + 100q + 75000) = 0.000012q^2 -0.06q + 100

b) The income function is given by the relation R (q) = P (q) q = -0.005q^2 + 200q.

The marginal revenue function for the company is given by the derivative of the revenue function, in this way the marginal revenue function is:

\frac{dR(q)}{dq}= -0.01q+200

 

(c) The profit function of the company is given by the relation U (q) = R (q) - C (q), and the marginal utility function is given by the derivative of the utility function, in this way , the marginal utility function is:

\dfrac{dU(q)}{dq}=R'(q) - C'(q) = -0.01q+200 - (0.000012q^2-0.06q+100) = -0.000012q^2+0.05q+100

When q = 2000, the marginal utility is:

U'(2000)=-0.000012(2000)^2+0.05(2000)+100 = 152

When q = 7000, the marginal utility is:

U'(7000)=-0.000012(7000)^2+0.05(7000)+100 = -138

6 0
3 years ago
I need help again.lol
Monica [59]

Answer:

13\ units

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

Where ((x_1,y_1)) and ((x_2,y_2)) are the points which one needs to find the distance between. In this case, these points are as follows:

k\ (-3,5)

j\ (-8, -7)

Substitute these points into the formula and solve for the distance between these points,

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

Simplify,

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

D=\sqrt{(-3+8)^2+(5+7)^2

D=\sqrt{(5)^2+(12)^2

D=\sqrt{25+144}

D=\sqrt{169}

D=13

8 0
2 years ago
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