The square root is 
Just square the top and bottom of the fraction. 
and 
so we have 12/16 and then we reduce to 3/4
The weight, y, in pounds, of kittens was tracked for the first 8 weeks after birth where t represents the number of weeks after
1 answer:
Answer:
Step-by-step explanation:
The mentioned relationship for the weight, in pounds, of the kitten with respect to time, in weeks, is
Weight of the kitten after 10 weeks
pounds
This modeled equation is based on the observation of the early age of a kitten where the kitten is in its growth period, but in the early stage the growth rate in the weight of the kitten was the same but the growth of any living beings continues till the adult stage. So, after some time, in real life situation, this weekly change in weight will become zero, So, this model is not suitable to measure the weight of the kitten over the larger time period.
Here, t= 10 weeks is nearby the observed time period, so the linearly modeled equation can be used to predict the weight.
Hence, the weight of the kitten after 10 weeks is 16.5 pounds.
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Answer:
The perimeter is 22
Step-by-step explanation:
Using a graph would be the easiest way to solve this type of problem (just count the units from each point and add them all up). Perimeter= 2l+2w
If graph paper is not available then you may need to use your head a little bit and imagine a graph. You want to first find the length (or width because either can be it) by finding the two points with similar x or y values.
One of the lengths can be found by using (-1,-9) and (4,-9) because they have similar y values. Next you want to find the distance between the two values so that you can find the length. When two points are in different quadrants (use the image for reference) you would add the x values by their absolute values in meaning the distance the number is from 0 or that you change the negative numbers into positive numbers. Add 1 and 4 and you get 5. The length is 5 which you then multiply by 2 and get the length of both sides.
Because you have the two lengths the width where both of the x values are similar and find the distance between the points. You can use the two points (-1,-9) and (-1,-3). Use the absolute value of the two y values and subtract them because they are in the same quadrant (refer to the image if needed). Use the largest absolute value and subtract the lowest absolute value so that you get 9-3 which would give you 6. The width is 6 and you then multiply it by 2 so that you get 12. 12 is the width of both sides of the rectangle. Add all 4 sides together to get a perimeter of 22.
