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matrenka [14]
3 years ago
6

The weight, y, in pounds, of kittens was tracked for the first 8 weeks after birth where t represents the number of weeks after

birth. The linear model representing this relationship is ŷ = 1.7 + 1.48t. Statler wanted to predict the weight of a kitten at 10 weeks. What is this an example of, and is this method a best practice for prediction? Explain your reasoning.
Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

Step-by-step explanation:

The mentioned relationship for the weight, in pounds, of the kitten with respect to time, in weeks, is

\hat y =1.7 +1.48t

Weight of the kitten after 10 weeks

\hat y =1.7 +1.48\times 10

\hat y =16.5 pounds

This modeled equation is based on the observation of the early age of a kitten where the kitten is in its growth period, but in the early stage the growth rate in the weight of the kitten was the same but the growth of any living beings continues till the adult stage. So, after some time, in real life situation, this weekly change in weight will become zero, So, this model is not suitable to measure the weight of the kitten over the larger time period.

Here, t= 10 weeks is nearby the observed time period, so the linearly modeled equation can be used to predict the weight.

Hence, the weight of the kitten after 10 weeks is 16.5 pounds.

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A and B are two events.
svlad2 [7]

Answer:

A and B are not independent events because P(A|B)≠P(A)

is the correct answer.

Step-by-step explanation:

If A and B are independent then we must have

P(AB) = P(A) P(B) and also

P(A/B) = P(A)

We are given that

A and B are two events.

Let P(A)=0.5 , P(B)=0.25 , and P(A and B)=0.15 .

P(A/B) = P(AB)/P(B) = 0.15/0.5 = 0.3

i.e. P(A/B) is not equal P(A)

Similarly P(B/A) = P(AB)/P(A) = 0.15/0.25 = 0.6 not equal to P(B)

Hence A and B are not independent.


5 0
3 years ago
1 15/100 + 1/50 +1.175=
grin007 [14]

1\frac{15}{100}+\frac{1}{50}+1.175 =\frac{115}{100}+\frac{1}{50}+1.175 =\frac{23}{20}+\frac{1}{50}+1.175 =\frac{115}{100}+\frac{2}{100} =\frac{115}{100}+\frac{2}{100} =\frac{115+2}{100}  =1.175+\frac{117}{100} =1.175+1.17  =2.345

<h3><em>You can write </em>2.345<em> or </em>2\frac{69}{200}<em></em></h3><h3><em></em></h3><h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>
6 0
3 years ago
Paola is selling bags of homemade caramel corn for a club fundraiser. The amount she makes depends on the number of bags sold. B
BlackZzzverrR [31]

Answer:

She realised $12 from selling 8 bags of caramel corn

Step-by-step explanation:

Given

(8, 12)

Required

Determine what it means based on the available information

A function is always written as (x,y)

Where x is dependent on y

By comparison,

x = bags of caramel corn = 8

y = amount realised = 12

Assuming the currency is in dollars

Conclusively,

She realised $12 from selling 8 bags of caramel corn.

5 0
3 years ago
The residual plot for a data set is shown.
BaLLatris [955]
The correct answer is: <span>D. The regression line is not a good model because the points in the residual plot form a curve.  (i know this because i just passed the test ;) )</span>
5 0
3 years ago
Read 2 more answers
The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
  • Mr.C earns 13000₹

therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0
2 years ago
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