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matrenka [14]
3 years ago
6

The weight, y, in pounds, of kittens was tracked for the first 8 weeks after birth where t represents the number of weeks after

birth. The linear model representing this relationship is ŷ = 1.7 + 1.48t. Statler wanted to predict the weight of a kitten at 10 weeks. What is this an example of, and is this method a best practice for prediction? Explain your reasoning.
Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

Step-by-step explanation:

The mentioned relationship for the weight, in pounds, of the kitten with respect to time, in weeks, is

\hat y =1.7 +1.48t

Weight of the kitten after 10 weeks

\hat y =1.7 +1.48\times 10

\hat y =16.5 pounds

This modeled equation is based on the observation of the early age of a kitten where the kitten is in its growth period, but in the early stage the growth rate in the weight of the kitten was the same but the growth of any living beings continues till the adult stage. So, after some time, in real life situation, this weekly change in weight will become zero, So, this model is not suitable to measure the weight of the kitten over the larger time period.

Here, t= 10 weeks is nearby the observed time period, so the linearly modeled equation can be used to predict the weight.

Hence, the weight of the kitten after 10 weeks is 16.5 pounds.

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Marci has a total 50 stamps, consisting of 25 cent stamps and halves the number of 15 cent stamps, they will be worth of $16.50.
lukranit [14]

Answer:

Originally there were 30, 25 cents stamps and 20, 15 cent stamps.

Step-by-step explanation:

We are given the following in the question;

Let x be the number of 25 cents stamps and y be the number of 15 cents stamps.

Marci has a total 50 stamps.

Thus, we can write

x+y=50

Also,

x = \dfrac{y}{2}

Total cost = $16.50

Thus, we can write the equation:

0.25x + 0.15y = 16.50

Solving the two equations:

0.25\dfrac{y}{2} + 0.15y = 16.50\\\\(0.125+0.15)y = 16.50\\y = 60\\x = 30

Originally,

x+y = 50\\30 + y = 50\\y = 20

Thus, originally there were 30, 25 cents stamps and 20, 15 cent stamps.

7 0
3 years ago
Area of a square with the length of 100cm and a width of 2cm
Rashid [163]

Answer:

200cm^{2}

Step-by-step explanation:

the formula for working out the area is to multiply the length by the width.

so for this you would multiply 100 by 2 which gives you 200 cm squared

100*2=200cm^{2}

4 0
3 years ago
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35. Luke and Matthew ran a lemonade
gogolik [260]
70% 30 = 21 I highly recommended using google it’s so much easier then this app sometimes because you won’t have to answer other people’s questions hahaha I’m only using it bc I can’t find the answers on google for my homework
6 0
3 years ago
Find the GCF of <img src="https://tex.z-dn.net/?f=18x%5E%7B3%7D" id="TexFormula1" title="18x^{3}" alt="18x^{3}" align="absmiddle
melamori03 [73]

18x^3 = 6x^3 *  1

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So GCF = 6x^3


Answer

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3 years ago
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A pole that is 3.4 m tall casts a shadow that is 1.54 m long. At the same time, a nearby building casts a shadow that is 35.75 m
inna [77]

Answer:

The building would be 78.92 meters tall.

Step-by-step explanation:

If the shodow of a 3.4m tall pole is 1.54m tall, and you have the shadow's height, then you make a cross, multiply-divide ratio table.

5 0
3 years ago
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