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mel-nik [20]
3 years ago
5

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

Answer:

-10,-12,-14,-16,-18,-20,-22,-24,-26,-28

Step-by-step explanation:

The common difference is what you get when you take the term and subtract the previous term from it.

For example, -12-(-10)= -2, and so on

Hope that helps!

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Lcm of 63, 80 and 102
photoshop1234 [79]

Answer:

85,680

Step-by-step explanation:

3 0
2 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
3 years ago
PLEASE HELP Find the length of PQ in circle R to the nearest hundredths
Vladimir [108]
There's no way to do that without seeing the drawing or hearing a lot more information. For one thing, we don't even know the size of the circle yet.
5 0
3 years ago
Work out the value of 4^0 x 16^0
NNADVOKAT [17]

Answer:

1

Step-by-step explanation:

Anything to the power of 0 is 1. <em>So</em>,

1 x 1 = 1

8 0
3 years ago
Read 2 more answers
Hudson was working on the problem 1/8y=4 He thought he should multiply bolth sides of the equation by 8 to get 32.
kaheart [24]

Answer: Use the given functions to set up and simplify

32. 1/8y = 4He= y =32He8= y =32He32=y=32He

7 0
3 years ago
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