3 years ago

Round The Following Number: 194,332.125

Mathematics

1 answer:

ddd [48]3 years ago

8 0

1554657/8

explanation

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Find the exact value of cos(theta) for an angle (theta) with tan (theta)= -2/3 and with its terminal side in Quadrant II.

Naya [18.7K]

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$-\frac{3\sqrt{13}}{13}$ .

Step-by-step explanation:

Since we are in quadrant two, cosine value is negative while sine value is positive.

We are going to use the Pythagorean Identity: $1+\tan^2(\theta)=\sec^2(\theta)$ .

$1+(\frac{-2}{3})^2=\sec^2(\theta)$

$1+\frac{4}{9}=\sec^2(\theta)$

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Since cosine and secant are reciprocals then they will have the same sign as along as they both exist.

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I don't see this answer as I'm going to rationalize the denominator.

$\cos(\theta)=-\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}$ .

$\cos(\theta)=-\frac{3\sqrt{13}}{13}$ .

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4 years ago

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