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Ulleksa [173]
2 years ago
14

Help me answer this question.

Mathematics
1 answer:
neonofarm [45]2 years ago
3 0

Answer:

<h2>8 units²</h2>

Step-by-step explanation:

Let side of the square = a

The , Area of square = a²

Now, Midpoint of Diagonal DB is E

And DE = 2 units

So, DB = 2 DE = 2 × 2 = 4 units

Now, using Pythagoras theorem in ∆ BCD

DB² = DC² + BC²

plug the values

{4}^{2}  =  {a}^{2}  +  {a}^{2}

Collect like terms

{4}^{2}  = 2 {a}^{2}

Evaluate the power

16 = 2 {a}^{2}

Swipe the side of the equation

2 {a}^{2}  = 16

Divide both sides of the equation by 2

\frac{2 {a}^{2} }{ 2 }  =  \frac{16}{2}

Calculate

{a}^{2}  = 8

Therefore, The area of the square is 8 sq.units.

Hope this helps..

Best regards!!

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Can someone please help me I do not understand
Readme [11.4K]

The perimeter of a figure is the distance all the way around the figure.

Area is how many units takes up the figure.

Example of perimeter: (attached)

Example of area: (attached, with squares in square)

In this case, the <em>area depends on the perimeter</em>. Count two sides of the rectangle. (Horizontal, and vertically.) Then write what the perimeter is for that. <u>Multiply</u> the two numbers and that will be your area.

Vertically, it is 11. Horizontally, it is 9. I would like you to try to see what to do next, if not, comment!

I hope this helped!

8 0
2 years ago
36 - 40. In order to save for her high school graduation, Marie decided to save P200 pesos at the end of each month. If the
PtichkaEL [24]

Answer:

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Step-by-step explanation:

Given data

P= P200

r= 0.25%

t= 1 year

n= 12

A= P(1+ r/n)^nt

substitute

A= 200(1+ 0.0025/12)^12*1

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7 0
2 years ago
22. Determine the value of c so that the line
tiny-mole [99]

Answer:

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Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

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\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0
3 years ago
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BabaBlast [244]

Answer:

A

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Both points are positive in the 1st quadrant.

7 0
3 years ago
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