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Ulleksa [173]
3 years ago
14

Help me answer this question.

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

<h2>8 units²</h2>

Step-by-step explanation:

Let side of the square = a

The , Area of square = a²

Now, Midpoint of Diagonal DB is E

And DE = 2 units

So, DB = 2 DE = 2 × 2 = 4 units

Now, using Pythagoras theorem in ∆ BCD

DB² = DC² + BC²

plug the values

{4}^{2}  =  {a}^{2}  +  {a}^{2}

Collect like terms

{4}^{2}  = 2 {a}^{2}

Evaluate the power

16 = 2 {a}^{2}

Swipe the side of the equation

2 {a}^{2}  = 16

Divide both sides of the equation by 2

\frac{2 {a}^{2} }{ 2 }  =  \frac{16}{2}

Calculate

{a}^{2}  = 8

Therefore, The area of the square is 8 sq.units.

Hope this helps..

Best regards!!

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