"2 minus root 3" => 2 - sqrt(3)
x does not appear here. That could cause a problem.
Unsure of what you mean by "x minus one upon X whole cube." Would you please go back to the original question and ensure that you have copied it down precisely. Without "x" in your equation, there's nothing to solve for.
It is given that John wants to find the center of a wall so he can hang a picture. So, John measures the wall and <u>determines</u> it is 65.25 inches wide. Since John has determined that the wall measures a particular amount that means that John has <u>quantified</u> the width of the wall, which in this case comes out to be 65.25 inches.
Again, this is a single number. This means that the width of the wall is a <u>discrete</u> quantity.
Thus, 65.25 inches or 65.25" is a Quantitative and Discrete type of data. Thus, out of the given options, the first option is the correct one.
Answer:

Step-by-step explanation:
An Albert Einstein iconic math problem.
Answer:
4
Step-by-step explanation:
The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept. In our equation, y = − 7 x + 4 , we see that the y-intercept of the line is 4.
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Answer:
Step-by-step explanation:
The formula for determining the area of a rectangle is expressed as
Area = 2(L + W)
Where
L represents the length of the rectangle.
W represents the width of the rectangle.
A proper rectangle has a length of 6 inches and a with of 8 inches. The area of the rectangle would be
6 × 8 = 48 inches^2
A square with a side length of 3 inches was cut of it. The formula for determining the area of a square is l^2
Therefore,
Area of square = 3^2 = 9 inches ^2
The area of the remaining paper would be
48 - 9 = 39 inches^2