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Rudiy27
3 years ago
6

2.247 divided into 7 equals what​

Mathematics
1 answer:
Bess [88]3 years ago
5 0
I think it’s 200.000
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78 – 24 divided by (14 – 6) x 2
RideAnS [48]

Answer:

76.5

Step-by-step explanation:

pls brainliest

4 0
2 years ago
Alexander spent $28 for 8 gal of gas. Decide if each statement about the ratio relationship is true or false. "Alexander has $45
sveticcg [70]

Answer:

false

Step-by-step explanation:

he needs at least 45.5 to fill his 13 gallon tank.

6 0
3 years ago
A store carries four brands of DVD​ players, J,​ G, P and S. From past​ records, the manager found that the relative frequency o
mr_godi [17]

Answer:

The answer is below

Step-by-step explanation:

A store carries four brands of DVD​ players, J,​ G, P and S. From past​ records, the manager found that the relative frequency of brand choice among customers varied. Using the given probability values for each of the four​ brands, find the probability that a random customer will choose brand J or brand P.

P(J)=0.22​, ​P(G)=0.18​, ​P(P)=0.35​, ​P(S)=0.25

Answer: Probability is the ration of possible outcomes to the total number of possible outcomes. The probability of mutually exclusive events i.e. events that cannot occur at the same time is the sum of their individual probabilities. If two events A and B are mutually exclusive events, then:

P(A or B) = P(A) + P(B)

Given that P(J)=0.22​, ​P(G)=0.18​, ​P(P)=0.35​, ​P(S)=0.25, the probability that a random customer will choose brand J or brand P is given by:

P(J or P) = P(J) + P(P) = 0.22 + 0.35 = 0.57

4 0
3 years ago
Which of the following representations are functions?
Hitman42 [59]
The answer to this question is a and c only
7 0
3 years ago
In a pizza takeout restaurant, the following probability distribution was obtained for the number of toppings ordered on a large
Elis [28]

Answer:

The random variable (number of toppings ordered on a large pizza) has a mean of 1.14 and a standard deviation of 1.04.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The probability distribution is:</em>

<em>x   P(x) </em>

<em> 0   0.30 </em>

<em>1    0.40 </em>

<em>2   0.20 </em>

<em>3   0.06 </em>

<em>4   0.04</em>

The mean can be calculated as:

M=\sum p_iX_i=0.3\cdot 0+0.4\cdot 1+0.2\cdot 2+0.06\cdot 3+0.04\cdot 4\\\\M=0+0.4+0.4+0.18+0.16\\\\M=1.14

(pi is the probability of each class, Xi is the number of topping in each class)

The standard deviation is calculated as:

s=\sqrt{\sum p_i(X_i-M)^2}\\\\s=\sqrt{0.3(0-1.14)^2+0.4(1-1.14)^2+0.2(2-1.14)^2+0.06(3-1.14)^2+0.04(4-1.14)^2}\\\\s=\sqrt{0.3(-1.14)^2+0.4(-0.14)^2+0.2(0.86)^2+0.06(1.86)^2+0.04(2.86)^2}\\\\ s=\sqrt{0.3(1.2996)+0.4(0.0196)+0.2(0.7396)+0.06(3.4596)+0.04(8.1796)}\\\\s=\sqrt{0.3899+0.0078+0.1479+0.2076+0.3272}\\\\ s=\sqrt{ 1.0804 }\\\\s\approx 1.04

3 0
2 years ago
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