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elena-14-01-66 [18.8K]
4 years ago
6

In the transactional process model of communication, the meaning of a message resides with the ___________.

Computers and Technology
1 answer:
pychu [463]4 years ago
4 0

Answer:

Encrypted content.

Explanation:

Transactional communication process is a linear mode of communication between two or more people or machine. It comprises of a sender, a receiver, a channel and the message itself.

It makes turns, transacting the next sender and receiver in the communication process. When the sender encoded a message, it transmits the encoded or encrypted message to the receiver, who receives the message and decided it. Then the receiver becomes the sender, and is able to send a message to the receiver, formerly the sender.

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Answer: 14 channels are available in the unlicensed 2.4 GHz ISM band.
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Determine the efficiency and big-O notation for the following algorithm:
Anon25 [30]

Answer and Explanation:

To calculate Big O, go through each line of code and determine O(!), O(n) and return your calculation.

For example,

In O (5 +6n), where 6 5 represent five instances of O(1), and 6 represent the 6 O(n).

We compute the time complexity of the algorithm. We get the result, just an estimation. In given algorithms, run time in milliseconds has been provided, such as in T (1) algorithm process in 512 milliseconds and T(2) algorithms process 8129 milliseconds. But big O notation not measured in milliseconds. Information given is not enough to calculate the big O notation.

       

8 0
4 years ago
You will complete 3 tasks. Task 1: Determine if the input number is prime or not You will ask the user for an integer You will d
GuDViN [60]

Answer:

Program is written in C++

#include<iostream>

using namespace std;

int main()

{

//1. Prime Number

int num;

cout<<"Input Number: ";

cin>>num;

int chk = 0;

for(int i =2; i <num;i++)

{

 if(num%i==0)

 {

  chk = 1;

  break;

 }

}

if(chk == 0)

{

 cout<<num<<" is prime"<<endl;

}

else

{

 cout<<num<<" is not prime"<<endl;

}

//2. Greatest Common Factor

int num1, num2, x, y, temp, gcf;  

cout<<"Enter two numbers: ";

cin>>num1;

cin>>num2;

x = num1;

y = num2;

while (y != 0) {

   temp = y;

   y = x % y;

   x = temp;

 }

 gcf = x;

 cout<<"Greatest Common Factor: "<<gcf<<endl;

 

// 3. LCM  

cout<<"Enter two numbers: ";

cin>>num1;

cin>>num2;

x = num1;

y = num2;

while (y != 0) {

   temp = y;

   y = x % y;

   x = temp;

 }

 gcf = x;

 int lcm =(num1 * num2)/gcf;

cout<<"Least Common Multiple: "<<lcm<<endl;

return 0;

}

Explanation:

<em>I've added the full source code as an attachment where I make use of comments to explain some lines</em>

Download cpp
6 0
3 years ago
Random Star
Tatiana [17]

Answer:

Explanation:

The following code is written in Java. The function takes in the random object and creates a random number where it generates a random number and prints out the * characters, if the random number and the input num are the same it prints out both values and ends the function.

import java.util.Random;

class Brainly {

   public static void main(String[] args) {

       Random r = new Random();

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       System.out.println();

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       while (true) {

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               System.out.print("\n");

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               for (int x = 0; x < randomNum; x++) {

                   System.out.print("*");

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               System.out.print("\n");

               System.out.println("Random Number: " + randomNum);

               System.out.println("Input Number: " + num);

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           }

       }

   }

}

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