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DerKrebs [107]
3 years ago
14

Which of the following are disadvantages of networks? Check all of the boxes that apply.

Computers and Technology
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

• Network intruders can access all computers on a network.

• Networks are costly to set up.

Explanation:

A network can be defined as a connection between the internet and the computer. A network is a means by which information or data are transmitted from one computer to another.

We have various types of networks and some of them are:

a) Local Area Network (LAN)

b) Wireless Local Area Network (WLAN)

c) Wide Area Network (WAN)

d) Campus Area Network (CAN)

e) Metropolitan Area Network (MAN)

f) Personal Area Network (PAN) e.t.c

The disadvantages of network are:

a) Network intruders such as computer hackers can easily access all computers on a network.

b) Networks are costly to set up.

It is of outermost importance that a network used by a computer is secured using security such as encryption in other to prevent data loss , hackers and exposure of information that are sensitive to computer users.

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A brief communication used in businesses is called a _____.
Bad White [126]

Answer:

C. Memo

Explanation:

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have me
RSB [31]

Answer:

Explanation:

The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.

import java.io.*;

import java.util.*;

class Rainfall

{

   Scanner in = new Scanner(System.in);

   private int month = 12;

   private double total = 0;

   private double average;

   private double standard_deviation;

   private double largest;

   private double smallest;

   private double months[];

   public Rainfall()

   {

       months = new double[12];

   }

   public void setMonths()

   {

       for(int n=1; n <= month; n++)

       {

           int answer = 0;

           while (true) {

               System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );

               answer = in.nextInt();

               if (answer > 0) {

                   months[n-1] = answer;

                   break;

               }

           }

       }

   }

   public void getTotal()

   {

       total = 0;

       for(int i = 0; i < 12; i++)

       {

           total = total + months[i];

       }

       System.out.println("The total rainfall for the year is " + total);

   }

   public void getAverage()

   {

       average = total/12;

       System.out.println("The average monthly rainfall is " + average);

   }

   public void getLargest()

   {

       double largest = 0;

       int largeind = 0;

       for(int i = 0; i < 12; i++)

       {

           if (months[i] > largest)

           {

               largest = months[i];

               largeind = i;

           }

       }

       System.out.println("The largest amount of rainfall was " + largest +

               " inches in month " + (largeind + 1));

   }

   public void getSmallest()

   {

       double smallest = Double.MAX_VALUE;

       int smallind = 0;

       for(int n = 0; n < month; n++)

       {

           if (months[n] < smallest)

           {

               smallest = months[n];

               smallind = n;

           }

       }

       System.out.println("The smallest amount of rainfall was " + smallest +

               " inches in month " + (smallind + 1));

   }

   public static void main(String[] args)

   {

       Rainfall r = new Rainfall();

       r.setMonths();

       r.getTotal();

       r.getSmallest();

       r.getLargest();

       r.getAverage();

   }

}

8 0
3 years ago
Someone hacked into an employee's computer and erased all of their data. All data for the past three weeks was lost as that was
hichkok12 [17]

WWW/ World Wide Web.

7 0
3 years ago
You are considering implementing a backup scheme for a server. After researching options, you decide on a method that does not r
Alecsey [184]

Answer:

C. A cold site is a leased facility that contains only electrical and communications wiring, air conditioning, plumbing, and raised flooring. No communications equipment, networking hardware, or computers are installed at a cold site until it is necessary to bring the site to full operation.

Explanation:

3 0
3 years ago
Write a loop that sets each vector element to the sum of itself and the next element, except for the last element which stays th
Gekata [30.6K]

Answer:

Add the following lines of code to the already existing code segment

<em>for (i = 0; i < SCORES_SIZE-1; ++i) { </em>

<em>        bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);</em>

<em>  }</em>

Explanation:

To do the task in the question, we have to iterate through the vector from the first element i.e. element at index 0 to the second to the last element; i.e. element at last index - 1

We then add each element in this iteration with the next.

This iterates through the vector from 0 to SCORES_SIZE - 1

<em>for (i = 0; i < SCORES_SIZE-1; ++i) { </em>

<em>This adds each vector element with the next</em>

<em>        bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);</em>

<em>  }</em>

The above should be added before

<em>for (i = 0; i < SCORES_SIZE; ++i) { </em>

<em>        cout << bonusScores.at(i) << " "; </em>

<em>}</em>

<em />

<em>Also, I've made other modifications to the program.</em>

  • <em>Proper import of header files</em>
  • <em>Proper declaration of vector bonusScores</em>

<em />

<em>See attachment for complete source code</em>

Download cpp
6 0
3 years ago
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