PLEASE PLEASE HELP
1 answer:
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Answer:
4.6
Step-by-step explanation:
x³-6x=72
x³-6x-72=0 .... a solution between 4 and 5
x=4 x³-6x-72= 64-24-72 = -32
x=5 x³-6x-72= 125-30-72 = 23
we have to find an x value that makes x³-6x-72 --> 0
see the attachment, we can find the 0 value of x is between 4.63 and 4.64
‘to 1 decimal place’ of the solution is: 4.6 (4.63 is too small and 4.64 is too big)
