there are 750 students in class 7 and 625 students in class 8 what percent is class 7 of the class 8?

1 answer:

6 0

750 is ?% of 625

<em>Y = ?% * X</em>

Solving our equation for ?
?% = Y/X
?% = 750/625
? = 1.2

Convert decimal to percent:
<span>?% = 1.2 * 100 = 120%
</span>
Class 8 is 120% of Class 7.

If you want the percent of Class 8 to Class 7, it is:
625 is ?% of 750

<em> = ?% * X</em>

Solving the equation for ?
?% = Y/X
?% = 625/750
? = 0.8333

Convert decimal to percent:
<span>?% = 0.8333 * 100 = 83.33%

</span>Class 7 is 83.33% of Class 8.

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5. Find the value(s) of x so that the line containing the points (2x + 3, x + 2) and (0, 2) is

Dvinal [7]

Answer:

x = -2 or -9

Step-by-step explanation:

You want the values of x such that the line defined by the two points (2x+3, x+2) and (0, 2) is perpendicular to the line defined by the two points (x+2, -3-3x) and (8, -1).

<h3>Slope</h3>

The slope of a line is given by the slope formula:

m = (y2 -y1)/(x2 -x1)

Using the formula, the slopes of the two lines are ...

m1 = (2 -(x+2))/(0 -(2x+3)) = (-x)/(-2x-3) = x/(2x +3)

and

m2 = (-1 -(-3-3x))/(8 -(x+2)) = (2+3x)/(6 -x)

<h3>Perpendicular lines</h3>

The slopes of perpendicular lines have product of -1:

$\dfrac{x}{2x+3}\cdot\dfrac{2+3x}{6-x}=-1\\\\x(3x+2)=(2x+3)(x-6)\qquad\text{multiply by $(2x+3)(6-x)$}\\\\3x^2+2x=2x^2-9x-18\qquad\text{eliminate parentheses}\\\\x^2+11x+18=0\qquad\text{put in standard form}\\\\(x+2)(x+9)=0\qquad\text{factor}$