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hodyreva [135]
4 years ago
12

Jessica bought 4 packages of birthday invitations for 16.95 per package including tax each package contained 12 birthday invitat

ions one stamp coast 0.44 she plans to split the cost evenly with her mother how much money will Jessica mother need to give to Jessica
Mathematics
1 answer:
erma4kov [3.2K]4 years ago
7 0

Answer:

Jessica's mum will give her 44.46

Step-by-step explanation:

To solve this, we will first of all need to get the total cost of sending the birthday invitations across. After that, we can now split the cost into two.

Cost of sending birthday invitations:

Package cost = 16.95

Number of packages bought = 4

total sum spent on packages = 4 X 16.95 = 67.8

Each package contains 12 invitations.

There are 4 packages.

Total number of invitations = 12 X 4 = 48 invitations

One stamp cost 0.44.

Putting stamps on all 48 invitations will cost 0.44 X 48 = 21.12

Therefore the total cost will be  the total sum spent on packages +the total sum spent on stamps = 67.8 + 21.12 = 88.92

Her mum has agreed to pay half of this cost which is 88.92 / 2 = 44.46

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Drag each expression to show whether it is equivalent to 54x + 18, 18(3x – 1), or (6 • 9x) + (6 • 1).
gladu [14]

Answer:

54x + 18 equivalent to (6 • 9x) + (6 • 3)

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7 0
4 years ago
Function 1 is defined by the equations r=3/4t +5<br> Function 2 is defined by the following table
Dvinal [7]

Function 2 has a greater y-intercept

<h3>Graphs</h3>

Graphs can be used to represent functions, equations, tables and relations

<h3>Equations</h3>

The equation of function 1 is given as:

r =\frac 34t + 5

To calculate the y-intercept, we set t to 0.

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By comparison:

5.25 is greater than 5

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Read more about graphs and functions at:

brainly.com/question/3939432

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3 years ago
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Makovka662 [10]

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5 0
3 years ago
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mihalych1998 [28]
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4 years ago
If we sample from a small finite population without replacement, the binomial distribution should not be used because the events
liraira [26]

Answer:

0.0008

Step-by-step explanation:

The formula for a hypergeometric probability is

\frac{(_AC_x)(_BC_{n-x})}{_NC_n}

where N is the population, A is the number of objects of type A, B is the number of objects of type B, n is the sample size and x is the number of successes.

In this problem, N is 13.  A is 5, since there are 5 objects drawn, and B is 8, since there are 8 remaining objects.

The sample size, n, is 5, and x is 5:

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4 0
4 years ago
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