3 years ago

How do you find the length of a rectangle if its 2 units more than the width and the area is 72

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Let width equal X and length equal X+2. Use algebra 72 = X times X+2

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A third-grade class is told to send a valentine to every single one of their classmates. On Valentine’s Day, the class ends up w

FinnZ [79.3K]

306 is the total cards sent by all the students in the class. Lets say x is the number of students in class, therefore each student needs to send x-1 cards (since they do not send themselves a card). So depending on your level of math, you could either take the complex way to solve it using quadratic equations, or just find the number that if multiplied by itself then subtracted, gives you 306.
$(x \times x) - x = 306 \\ lets \: try \: 18 \\ (18 \times 18) - 18 = 306 \\ so \: x = 18$
===============
Complex way
$(x \times x) - x = 306 \\ {x}^{2} - x - 306 = 0$
So a = 1, b = -1, c=-306
using the quadratic equation:
$x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a}$
$x = \frac{1 + \sqrt{1 - (4 \times 1 \times - 306)} }{2} \\ x = \frac{1 + \sqrt{1 - ( - 1224)} }{2} \\ x = \frac{1 + \sqrt{1225} }{2} \\ x = \frac{1 + 35}{2} \\ x = \frac{36}{2} \\ x = 18$