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xxTIMURxx [149]
3 years ago
11

Which best describes how to create a fraction bar in which the shaded portion represents 5/7

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0
This answer beat destines how to creat a fraction bar 3/4
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Twins Bakery has 12 bags of flour in their bakery. Each bag weighs 4.53 pounds. They will use all of the flour to make 18 batche
amm1812

Answer:

1a) 54.36

1b) 3.02 per batch

Step-by-step explanation:

1a) 12 x 4.53= 54.36

1b) 54.36/18=3.02

Total amount of pounds divided by the amount of cinnamon roll batches

4 0
3 years ago
Read 2 more answers
You are selling tickets to a play. You have sold (3t+2) tickets for $5 each
Norma-Jean [14]

Answer:

25

Step-by-step explanation:

3 + 2 =5 so then you multiply 5 by 5 to get 25

5 0
3 years ago
Read 2 more answers
Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 4 right angle0,−4 in the directions pa
Nikolay [14]

Answer:

F_p = < - \sqrt{3} , -3 >\\\\F_o = < \sqrt{3} , -1 >

Step-by-step explanation:

- A plane is oriented in a Cartesian coordinate system such that it makes an angle of ( π / 3 ) with the positive x - axis.

- A force ( F ) is directed along the y-axis as a vector < 0 , - 4 >

- We are to determine the the components of force ( F ) parallel and normal to the defined plane.

- We will denote two unit vectors: ( u_p ) parallel to plane and ( u_o ) orthogonal to the defined plane. We will define the two unit vectors in ( x - y ) plane as follows:

- The unit vector ( u_p ) parallel to the defined plane makes an angle of ( 30° ) with the positive y-axis and an angle of ( π / 3 = 60° ) with the x-axis. We will find the projection of the vector onto the x and y axes as follows:

                         u_o = < cos ( 60° ) , cos ( 30° ) >

                         u_o = < \frac{1}{2} ,  \frac{\sqrt{3} }{2} >

- Similarly, the unit vector ( u_o ) orthogonal to plane makes an angle of ( π / 3 ) with the positive x - axis and angle of ( π / 6 ) with the y-axis in negative direction. We will find the projection of the vector onto the x and y axes as follows:

                        u_p = < cos ( \frac{\pi }{6}  ) , - cos ( \frac{\pi }{3} ) >\\\\u_p = < \frac{\sqrt{3} }{2}  , -\frac{1}{2}  >\\

- To find the projection of force ( F ) along and normal to the plane we will apply the dot product formulation:

- The Force vector parallel to the plane ( F_p ) would be:

                          F_p = u_p(F . u_p)\\\\F_p = < \frac{1}{2} , \frac{\sqrt{3} }{2} > [  < 0 , - 4 > . < \frac{1}{2} , \frac{\sqrt{3} }{2} > ]\\\\F_p = < \frac{1}{2} , \frac{\sqrt{3} }{2} > [ -2\sqrt{3}  ]\\\\F_p = < -\sqrt{3}  , -3 >\\

- Similarly, to find the projection of force ( F_o ) normal to the plane we again employ the dot product formulation with normal unit vector (  u_o  ) as follows:

                         F_o = u_o ( F . u_o )\\\\F_o = < \frac{\sqrt{3} }{2} , - \frac{1}{2} > [ < 0 , - 4 > . < \frac{\sqrt{3} }{2} , - \frac{1}{2} > ] \\\\F_o = < \frac{\sqrt{3} }{2} , - \frac{1}{2} > [ 2 ] \\\\F_o = < \sqrt{3} , - 1 >

- To prove that the projected forces ( F_o ) and ( F_p ) are correct we will apply the vector summation of the two orthogonal vector which must equal to the original vector < 0 , - 4 >

                       F = F_o + F_p\\\\< 0 , - 4 > = < \sqrt{3}, -1 > + < -\sqrt{3}, -3 >  \\\\< 0 , - 4 > = < \sqrt{3} - \sqrt{3} , -1 - 3 > \\\\< 0 , - 4 > = < 0 , - 4 >  .. proven                    

8 0
4 years ago
I need to know order pairs for this equation ​
kompoz [17]

Hi, you haven't provided the equation that you need order pairs for.

Therefore, I'll just explain how to find order pairs in general and you can apply the same method to the the equation you have

<u><em>Answer with explanation:</em></u>

Order pairs of any equation are (x,y) values that satisfy this equation

To get them, the simplest way is to assume a value for x, use this value to substitute in the equation you have and then solve for the corresponding y

<u>Example:</u>

<u>Consider the equation: x + 2y = 8</u>

at x = 0: 0 + 2y = 8 ............> 2y = 8 ..........> y = 4 ............> order pair is (0,4)

at x = 2: 2 + 2y = 8 ............> 2y = 6 ..........> y = 3 ............> order pair is (2,3)

at x = 4: 4 + 2y = 8 ............> 2y = 4 ..........> y = 2 ............> order pair is (4,2)

Now, we can say that (0,4), (2,3) and (4,2) are order pairs that satisfy the given equation

<u>For your equation:</u>

1- Assume value of x

2- Substitute with that value in the equation

3- Solve the equation for the corresponding y

4- The order par pair would be:

(assumed x value , corresponding calculated y value)

Hope this helps :)

3 0
3 years ago
Find the 7th term of the arithmetic sequence -5x-8,-x-14,3x-20,...
klemol [59]
A₁ = -5x-8;  a₂ = -x-14; a₇=?

d = a₂ - a₁
  = x-14 - (-5x-8)
  = -x - 14 + 5x + 8
  = 4x-6

a(n) = a₁ + (n-1)d

a₇ = -5x-8 + (7-1)(4x-6)
    = -5x-8 + 6(4x-6)
    = -5x - 8 + 24x - 36
    = 19x - 44
8 0
3 years ago
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