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sammy [17]
3 years ago
15

The printer sent out 150 newspapers one day. How many boxes would there be if they were packed in tens

Mathematics
2 answers:
krok68 [10]3 years ago
8 0
15 box because 150 divided by 10 is 15 because u take a zero off hope I helped
irga5000 [103]3 years ago
6 0
To solve this problem, you would divide the total number of newspapers by the amount of newspapers per box, in order to find the number of boxes.

150/10=15.

There would be 15 boxes.
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6 people share 17 packs of pencils equally how many packs of pencils does each person get?
forsale [732]

17/6 = 2.8333333

each person gets 2.8333333333 packs of pencils or you can write it as 2.83

4 0
3 years ago
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12 more than janelle's score is 74
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Answer:

janelles score is 62

Step-by-step explanation:

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A total of 308 tickets were sold for the school play. they were either adult tickets or student tickets. the number of student t
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4 years ago
6. Write the explicit formula for the geometric sequence of the height of the ball on the 10th bounce.First bounce: 54 inchescom
Nat2105 [25]

The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.

The explicit formular for the geometric sequence is shown as;

\begin{gathered} ar^{n-1} \\ \text{Where a is the first term in the sequence,} \\ r\text{ is the common ratio betw}een\text{ every successive term} \\ \text{And n is the nth term} \\ \text{The explicit formular for the height of the ball on the 10th bounce is;} \\ ar^{n-1} \\ 54\times(0.750)^{10-1} \\ 54\times(0.750)^9 \\ 54\times0.07508468\ldots \\ 4.0545 \end{gathered}

The explicit formula is shown as;

54 x (0.750)^9

The rest is simply to solve for the height on the 10th bounce

5 0
1 year ago
Over what interval will the immediate value theorem apply
koban [17]

Answer:

Any [a,b] that does NOT include the x-value 3 in it.

Either an [a,b] entirely to the left of 3, or

an  [a,b] entirely to the right of 3

Step-by-step explanation:

The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.

Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.

6 0
3 years ago
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