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IRISSAK [1]
2 years ago
9

IVE BEEN ASKING FOR AN HOUR PLEASE HELP! find the value of x​

Mathematics
1 answer:
Nikitich [7]2 years ago
3 0

Answer:

I think the value of x is 3

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The geometric mean of 8 and 2 is<br><br> 5<br> 3<br> 4<br> 16
igomit [66]

Answer:5

Step-by-step explanation:

<h3><u>(8 + 2)</u> <u>sum of values  </u>    =    <u>10</u>  =  5</h3><h3>    2    number of values        2</h3><h3 />

There is equal spacing between the mean and the extremes

8 - 5 = 3

5 - 2 = 3

5 0
3 years ago
Which is an advantage of using equations for solving problems?
Arisa [49]

Answer:

D.Every problem needs an equation in order to be able to solve it

4 0
2 years ago
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I have an easy and quick question. So the picture shows an answered question but how do you know to divide? I just don't underst
11111nata11111 [884]

Answer:

Ok so u know to divide bc u r trying to isolate the variable and that means undoing the function in this case 0.6 is multiplied to p so u do the opposite which is division

tada

Hope this helps :)

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8 0
2 years ago
Read 2 more answers
Write as a product: 25a2−0.01b10
Yakvenalex [24]

Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

so

25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

                               =\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)    ∵ \sqrt{0.01}=0.1,

Therefore, we conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

7 0
2 years ago
8 ABC please trig assignment
Papessa [141]

Using equivalent angles, the solutions are given as follows:

a) x = \frac{15\pi}{23}.

b) x = \frac{9\pi}{62}, x = \frac{53\pi}{62}.

c) x = \frac{3\pi}{8}, \frac{11\pi}{8}

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

For item a, we have to find the equivalent angle on the 2nd quadrant, where the sine is also positive.

Hence:

\pi - \frac{8\pi}{23} = \frac{23\pi}{23} - \frac{8\pi}{23} = \frac{15\pi}{23}

Hence x = \frac{15\pi}{23}.

For item b, if two angles are complementary, the sine of one is the cosine of the other.

Complementary angles add to 90º = 0.5pi, hence:

x + \frac{11\pi}{31} = \frac{\pi}{2}

x = \frac{31\pi}{62} - \frac{22\pi}{62}

x = \frac{9\pi}{62}

The equivalent angle on the second quadrant is:

\pi - \frac{9\pi}{62} = \frac{62\pi}{62} - \frac{9\pi}{62} = \frac{53\pi}{62}

Hence the solutions are:

x = \frac{9\pi}{62}, x = \frac{53\pi}{62}

For item c, the angles are also complementary, hence:

x + \frac{\pi}{8} = \frac{\pi}{2}

x = \frac{4\pi}{8} - \frac{\pi}{8}

x = \frac{3\pi}{8}

The tangent is also positive on the third quadrant, hence the equivalent angle is:

x = \pi + \frac{3\pi}{8} = \frac{8\pi}{8} + \frac{3\pi}{8} = \frac{11\pi}{8}

Hence the solutions are:

x = \frac{3\pi}{8}, \frac{11\pi}{8}

More can be learned about equivalent angles at brainly.com/question/28163477

#SPJ1

6 0
1 year ago
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