Question

You have 432 carnations and 192 rose you have to make bouquets with the same number and no flowers can be left?

Answer 1

Answer:

I can make maximum 48 bouquets with 9 carnations and 4 rose in each of them.

Step-by-step explanation:

I have 432 carnations and 192 rose I have to make bouquets with the same number and no flowers can be left.

Now, the prime factors of 432 are 2, 2, 2, 2, 3, 3, 3. And the prime factors of 192 are 2, 2, 2, 2, 2, 2, 3.

Therefore, the largest common factor of 432 and 192 is 2 × 2 × 2 × 2 × 3 = 48.

Therefore, I can make maximum 48 bouquets with $\frac{432}{48} = 9$ carnations and $\frac{192}{48} = 4$ rose in each of them. (Answer)