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Lapatulllka [165]
4 years ago
13

At the Fidelity Credit Union, a mean of 7.1 customers arrive hourly at the drive-through window. What is the probability that, i

n any hour, less than 2 customers will arrive
Mathematics
1 answer:
Sergio [31]4 years ago
4 0

Answer:

The probability that, in any hour, less than 2 customers will arrive is 0.0067.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of customers arriving hourly at the drive-through window at the Fidelity Credit Union.

The random variable <em>X</em> describes a finite number of occurrences of an event in a fixed time interval.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 7.1.

The probability mass function of <em>X</em> is:

P(X=x)=\frac{e^{-7.1}(7.1)^{x}}{x!};x=0,1,2,3...

Compute the probability of less than 2 customers arriving as follows:

P(X

                =\frac{e^{-7.1}(7.1)^{0}}{0!}+\frac{e^{-7.1}(7.1)^{1}}{1!}\\\\=0.00083+0.00586\\\\=0.00669\\\\\approx 0.0067

Thus, the probability that, in any hour, less than 2 customers will arrive is 0.0067.

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