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3 years ago

Write the equation of the line parallel to 9x - 3y = 27 which passes through the point (6,2)

Mathematics

2 answers:

Nana76 [90]3 years ago

8 0

Answer:

y=3x-16

Step-by-step explanation:

-3y=-9x+27

y=3x-9

slope: 3

y-2=3(x-6)

y-2=3x-18

y=3x-16

inn [45]3 years ago

5 0

bearing in mind that, parallel lines have the same slope, hmmm what's the slope of 9x - 3y = 27 anyway?

$\bf 9x-3y=27\implies -3y=-9x+27\implies y=\cfrac{-9x+27}{-3} \\\\\\ y=\cfrac{-9x}{-3}+\cfrac{27}{-3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{3}x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

well, a parallel line to that one will also have the same slope, namely, we're really looking for the equation of al line whose slope is 3 and runs through (6,2).

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{3}(x-\stackrel{x_1}{6}) \\\\\\ y-2=3x-18\implies y=3x-16$

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3 years ago

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3 years ago

A line through the origin and (10,4) is showin in the standard (x,y) coordinate plane below. The acute angle between the line an

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Answer:

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