Question

Find the equation in stope intercept form of the line that passes through the points (-2,4) and (6,2),

Answer 1

Answer:

y = -x/4 + 7/2

Step-by-step explanation:

Find the slope

( -2 , 4) ( 6 , 2)

m = (y2 - y1)/(x2 - x1)

x1 = -2

y1 = 4

x2 = 6

y2 = 2

m = ( 2 - 4)/( 6 -(-2)

m = ( 2 -4)/(6 +2)

= -2/8

= -1/4

Using point slope form equation

y - y1 = m( x - x1)

Using the second point

( 6 , 2)

x1= 6

y1=2

m = -1/4

y - 2 = -1/4(x - 6)

y - 2 = -(x - 6)/4

Open the bracket with -

y - 2 = (-x + 6)/4

y = ( -x + 6)/4 + 2

LCM = 4

y =( -x + 6 + 8)/4

y = (-x + 14)/4

Rearrange using slope intercept form

y = mx + c.

y = -x/4 + 14/4

We can break 14/4 by dividing by 2

y = -x/4 + 7/2