Question

The volume of a sample of N2 gas was decreased from 13.81 to 3.63 L. If the final pressure exerted by the N2 sample was 261.1 kPa, what pressure did the N2 exert before its volume was decreased?

Answer 1

Answer: 68.6 kPa

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=?\\V_1=13.81L\\P_2=261.1kPa\\V_2=3.63L$

Putting values in above equation, we get:

$P_1\times 13.81L=261.1\times 3.63L\\\\P_1=68.6kPa$

Thus pressure  before its volume was decreased was 68.6 kPa