Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
Step-by-step explanation:
a. 2(y-8)
= 2y-16
b. 3(x-5)
= 3x-15
c.6(b-4)
= 6b-32
d.7(d-2)
= 7d-14
e.5(2-y)
= 10-5y
f.3(4-t)
= 12-3t
g.5(b-a)
=5b-5a
h.7(2-h)
= 14-7h
Well number one is an acute angle number two is obtuse and number three is obtuse
Answer:
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
Step-by-step explanation:
Given:
Number is
200.06
For option A)
2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
= 200 + 0 + 0 + 0.06
= 200.06
Which is CORRECT.
For option B)
2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000
= 200 + 0 + 0 + 0.006
=200.006
Which is INCORRECT.
For option C)
2 × 100 + 6 × 1/10
= 200 + 0.6
= 200.6
Which is INCORRECT.
For option D)
2 × 100 + 6 × 1/100
= 200 + 0.06
= 200.06
Which is CORRECT.
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
