Question

Pls help these are test corrections

Answer 1

Answer:

See explanation

Step-by-step explanation:

Given triangle has its vertices at points A(-4,-2), B(1,3) and C(3,-2).

Find all sides lengths:

$AC=\sqrt{(-4-3)^2+(-2-(-2))^2}=\sqrt{(-7)^2+(0)^2}=\sqrt{49+0}=\sqrt{49}=7\ units\\ \\AB=\sqrt{(-4-1)^2+(-2-3)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=5\sqrt{2}\ units\\ \\BC=\sqrt{(1-3)^2+(3-(-2))^2}=\sqrt{(-2)^2+(5)^2}=\sqrt{4+25}=\sqrt{29}\ units$

The longest side is AB.

By the Pythagorean theorem,

$AB^2=AC^2+BC^2\\ \\(5\sqrt{2})^2=7^2+\sqrt{29}^2\\ \\50=49+29\\ \\50=78$

This is false statemnt, so this triangle is not right triangle.