Answer:
a = 4, x = 1
Step-by-step explanation:
The opposite sides of a parallelogram are congruent , then
WX = YZ , that is
a² + 5a = 5a + 16 ( subtract 5a from both sides )
a² = 16 ( take the square root of both sides )
a = ±
= ± 4
Since a > 0 , then a = 4
Also
XY = WZ , that is
x² + 6x = 4x + 3 ( subtract 4x + 3 from both sides )
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Since x > 0 , then x = 1
Since

The square root of 11 is somewhere between 3 and 4. In order to round it to the nearest tenth, we have to try all numbers between 3 and 4 with one decimal digit, and see which is closest to 11 when squared. We have
![\begin{array}{c|c}n&n^2\\3&9\\3.1&9.61\\3.2&10.24\\3.3&10.89\\3.4&11.56\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Dn%26n%5E2%5C%5C3%269%5C%5C3.1%269.61%5C%5C3.2%2610.24%5C%5C3.3%2610.89%5C%5C3.4%2611.56%5Cend%7Barray%7D%5Cright%5D)
So, the square root of 11 is somewhere between 3.3 and 3.4.
The answer is B.
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Answer:
he could have five 20 bills at most
Answer:
the answer is C
Step-by-step explanation: