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3 years ago

Trey bought 18 packs of cola. Each pack had 8 cans. He drank 7 of the cans. How many cans are left?

Mathematics

1 answer:

MariettaO [177]3 years ago

5 0

Answer: 137 cans are left of cola.

Step-by-step explanation: First we want to find the total amount of cola Trey bought. Each pack contains 8 cans, so multiply 18 packs by 8 cans to find the total amount of cans he bought. 18 x 8 = 144 total cans of cola.

Since Trey drank 7 of the cans, simply subtract 7 from 144, 144 - 7 = 137 total cans of cola remaining.

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Arpitha lined up the interior angles of the triangle along the line below. Triangle A B C. Angle C is 99 degrees. 2 lines extend

uysha [10]

Answer:

Step-by-step explanation:

Because i took the test

8 0

3 years ago

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Yakvenalex [24]

Answer:

3) 522

4) 468

Step-by-step explanation:

hello!

3) in the question, it says the cross section is a square, and the area of PQRS is 81.

for the square, we know that the length and height have to be the same, so if the area is 81, then we know the sides are both 9 because 9*9 is 81 and they're the same numbers multiplied. (same height and length)

with the information that all 4 sides of the square is 9 and the other side is labeled 10, we can figure out the rest.

both squares : 81+81=162

both 10 by 9 sides: 90+90=180

both 10 by 9 sides (top and bottom): 90+90=180

total surface area=162+180+180=522

4) for this problem, we can see that the triangle is a right triangle.

to solve the area of the triangle, we can do (9*12)/2=108/2=54.

there are two sides with triangles, so we double 54 (54*2=108)

9 by 10 side: 90

10 by 12 side: 120

now for the last slide, theres no information on the length. the formula for the diagonal is

a^2+b^2=c^2

which is

9^2+12^2=81+144=255=15^2

with this, the area of the rectangular side gives us 10*15 which is 150.

adding it together, we get

108+90+120+150=468.

hope this helps!

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3 years ago

Which set of graphs can be used to find the solution set to 3e* > >-x?

kobusy [5.1K]

The attached graph represents the solution set of $3e^x > \frac 12^x$

<h3>How to determine the graph?</h3>

The complete options are not given.

So, I would plot the graph that represents the solution set

The inequality is given as:

$3e^x > \frac 12^x$

Start by splitting the inequalities as follows:

$f(x) > 3e^x$

$g(x) > \frac 12^x$

The above means that we plot the graphs of f(x) and g(x) to represent the solution set

See attachment