Answer:
a) Var[z] = 1600
D[z] = 40
b) Var[z] = 2304
D[z] = 48
c) Var[z] = 80
D[z] = 8.94
d) Var[z] = 80
D[z] = 8.94
e) Var[z] = 320
D[z] = 17.88
Step-by-step explanation:
In general
V([x+y] = V[x] + V[y] +2Cov[xy]
how in this problem Cov[XY] = 0, then
V[x+y] = V[x] + V[y]
Also we must use this properti of the variance
V[ax+b] = 
V[x]
and remember that
standard desviation = ![\sqrt{Var[x]}](https://tex.z-dn.net/?f=%5Csqrt%7BVar%5Bx%5D%7D)
a) z = 35-10x
Var[z] = 
Var[x] = 100*16 = 1600
D[z] = 
= 40
b) z = 12x -5
Var[z] = 
Var[x] = 144*16 = 2304
D[z] = 
= 48
c) z = x + y
Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] = 
= 8.94
d) z = x - y
Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] = = 8.94
e) z = -2x + 2y
Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320
D[z] = 
= 17.88
Answer:
5/6
Step-by-step explanation:
On a standard 6-sided die, there is only one 2. That means that there are 5 other numbers that it could land on (1, 3, 4, 5, 6).
Using that information, the probability of it not landing on a 2 is 5 out of 6 or 5/6. This is because you must do part over whole. The "part" in this situation is the 5 "wanted" numbers, and the "whole" is 6 because there are six potential numbers that it could land on.
I hope this helps.
<span>The product of 7 and 0.04 is 0.28=true</span>
Answer:
1,2,3,4,6,9,12,18,36
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
i would say 3 different ways because 4 x 3 = 12
Hope this helps!
