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Lana71 [14]
2 years ago
11

Complete the remainder of the table for the given function rule: y = 4 - 3 -4 0 4 8 12 0 0 y7 4 [?]​

Mathematics
1 answer:
Alex777 [14]2 years ago
5 0

Answer:

1, -2, -5

Step-by-step explanation:

To find the y value when given x, simply replace the x in the equation with the number given.

X = 4

y = 4 - \frac{3(4)}{4} = 4 - 12/4 = 4 - 3 = 1

x = 8

y = 4 - \frac{3(8)}{4} = 4 - 24/4 = 4 - 6 = -2

x = 12

y = 4 - \frac{3(12)}{4} = 4 - 36/4 = 4 - 9 = -5

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A regular nonagon has a perimeter of 36 cm and an
aniked [119]

Answer:

2.56

Step-by-step explanation:

6 0
3 years ago
write an equation for the line that passes through the given point and has the given slope m (4,-5);m= -1/4
EastWind [94]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{y = -1/4x - 4}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{Slope = -1/4, Point through = (4, -5)}

Find:  \textsf{Equation for the line that passes through the given point}

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - (-5) = -1/4(x - 4)}

<u>Simplify and solve for y</u>

  • \textsf{y + 5 = -1/4(x - 4)}
  • \textsf{y + 5 = -1/4x + 1}
  • \textsf{y + 5 - 5 = -1/4x + 1 - 5}
  • \textsf{y = -1/4x - 4}

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

5 0
2 years ago
Given f(x) = –2 – 1, find f(5).
sveta [45]
-2 - 1 = -3
The answer is -3.
3 0
3 years ago
Please help 20 points geometry triangle questions​
slava [35]

Answer:

1. yes, SAS

2. yes, ASA

3. yes, SSA

4. yes, SAS

5. no

6. yes, HL and SSA

7. yes, HL and ASA

8. yes, ASA

9. no

10. yes, SSS

11. yes, ASA

12. yes, HL and SSA

13. yes, SAS

14. no

15. no

16. no

17. yes, ASA

18. yes, ASA

19. yes, ASA

5 0
2 years ago
A gear with a diameter of 12.0 inches makes 35 revolutions every three minutes. Find the linear and angular velocities of a poin
alina1380 [7]

Answer:

Angular velocity: \omega = \frac{7\pi}{18} \,\frac{rad}{s} (1.222\,\frac{rad}{s})

Linear velocity: v = \frac{14\pi}{3}\,\frac{m}{s} (14.661\,\frac{m}{s})

Step-by-step explanation:

The gear experiments a pure rotation with axis passing through its center, the angular (\omega), in radians per second, and linear velocities (v), in inches per second, of a point on the outer edge of the element are, respectively:

\omega = \frac{2\pi}{60}\cdot \dot n (1)

v = R\cdot \omega (2)

Where:

\dot n - Rotation rate, in revolutions per minute.

R - Radius of the gear, in inches.

If we know that \dot n = \frac{35}{3}\,\frac{rev}{min} and R = 12\,in, then the linear and angular velocities of the gear are, respectively:

\omega = \frac{2\pi}{60}\cdot \dot n

\omega = \frac{7\pi}{18} \,\frac{rad}{s} (1.222\,\frac{rad}{s})

v = R\cdot \omega

v = \frac{14\pi}{3}\,\frac{m}{s} (14.661\,\frac{m}{s})

7 0
2 years ago
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