Answer:
yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehcsacasvavadvadvsdvsdvsdvdvdvyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh
Step-by-step explanation:
Answer:
168
Step-by-step explanation:
Sum the parts of the ratio, 6 + 7 = 13 parts
Divide the total number of students by 13 to find the value of one part of the ratio.
364 ÷ 13 = 28 ← value of 1 part of the ratio, thus
number of girls = 6 × 28 = 168
It would be B, because BC does not necessarily have to be equal to CE, as they are not congruent
In order to use the Law of Sines, EF has to be the included side. Therefore, we need to calculate angle F which is 72 degrees.
side f / sine (F) = side d / sine (D)
side f / sine (72) = side 24 / sine (45)
side f = sine (72) * 24 / sine (45)
side f = 0.95106 * 24 / .70711
side f (DE) =
<span>
<span>
<span>
32.2798998741
</span>
</span>
</span>
answer is C
K to the 6th power, because you can add k to k to the 5th power to make k to the 6th, and n to the 5th and n to the -5th cancel each other out.
