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saul85 [17]
4 years ago
12

W=B(L1-L2)/6 solve for L2

la1" title="w = b\frac{ l1 -l2 }{6} " alt="w = b\frac{ l1 -l2 }{6} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
son4ous [18]4 years ago
7 0
Solve for L2:
W = 1/6 B (L1 - L2)
W = 1/6 B (L1 - L2) is equivalent to 1/6 B (L1 - L2) = W:
1/6 B (L1 - L2) = W
Divide both sides by B/6:
L1 - L2 = (6 W)/B
Subtract L1 from both sides:
-L2 = (6 W)/B - L1
Multiply both sides by -1:
Answer: L2 = L1 - (6 W)/B
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Answer:

B = 781.347

Step-by-step explanation:

Since we already have an equation just plug in terms where needed.

B=17(243)^{\frac{4}{5}}

First, start by multiplying to get rid of the parentheses.  

B=4131^{\frac{4}{5}}

Now get rid of the power.

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Hope this helps with the problem.

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3 years ago
What’s the remainder for this synthetic division problem?
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3   |   1    5     -8     6

.    |         3    24   48

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That is to say,

\dfrac{x^3+5x^2-8x+6}{x-3}=x^2+8x+16+\dfrac{54}{x-3}

The remainder is 54.

Another way of doing it is to apply the polynomial remainder theorem, which says the remainder upon dividing a polynomial p(x) by x-c is exactly p(c). So recognizing that the listed coefficients refer to

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we find

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Airida [17]

Answer:

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