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DedPeter [7]
3 years ago
7

Please help me im stuck

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer: -60+87d

Step-by-step explanation: multiply -3 by 20 then do the same with -3 and -29d the your answer would be x+-d (letters used for explanation)

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If A = 8! and B = 8P8, then which one of the following is true:
meriva

Answer:

A. A = B

Step-by-step explanation:

Given

A = 8!

B = ^8P_8

Required

Which of the options is true

We start by simplifying B = ^8P_8

Permutation is calculated as follows

^nP_r = \frac{n!}{(n - r)!}

So.

^8P_8 =\frac{8!}{(8 - 8)!}

^8P_8 =\frac{8!}{0!}

0! = 1; So

^8P_8 =\frac{8!}{1}

^8P_8 =8!

Hence. B! = P!

<em>This implies that </em>A = B = 8!<em />

4 0
3 years ago
You get in an elevator and go down 8 floors. You exit on the 16th floor. Write and solve an equation to find what floor you got
disa [49]
So floor that you started is x
go down 8 means -8
end on 16

so
x-8=16
add 8
x=24

started on 24
3 0
4 years ago
Box A has a volume of 12 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were multiplied by five. W
postnew [5]
Volume of B is 125×12=1500
4 0
3 years ago
Read 2 more answers
PLEASE HELP it should be easy for someone but I can’t do it
-Dominant- [34]

Answer:

Total crackers on the plate are 12

Step-by-step explanation:

Manuel ate crackers = \frac{1}{3}

His brother ate crackers = \frac{1}{4}

Crackers left on the plate = 5

We need to find how many crackers were there on the plate.

Let x be the total crackers on the plate

So, we can write the equation

x-\frac{1}{3}x-\frac{1}{4}x=5

Because 1/3 and 1/4 crackers are eaten and 5 are left so, we subtract 1/3x and 1/4x from x and equal it to 5

\frac{12x-4x-3x}{12}=5\\\frac{12x-7x}{12}=5\\\frac{5x}{12}=5\\x=\frac{5*12}{5}\\x=12

So, we get x = 12

Therefore, total crackers on the plate are 12

8 0
3 years ago
The perimeter of a rectangle is 108 inches. the rectangle is 34 inches long. how wide is it?
mixer [17]

\frac{108 - 34 - 34}{2}
= 20 inches

In a rectangle, there are 2 similar length measurements & 2 similar width measurements
7 0
4 years ago
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