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Helga [31]
3 years ago
14

In gymnastics competition,paige's score was 37.025 what is page's score written in word form

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0
Thirty-seven point zero two five
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Figure ABCD is a parallelogram. What is the value of x? A B O 6 ET O 7 8 5x + 3 38 09 D С​
kondor19780726 [428]

Answer:

Given: It is given that  and .

To Prove: ABCD is a parallelogram.

Statements                                                                            

1.  and            

Reason: Given                                      

2.  are alternate interior angles      

Reason: Def of alternate interior angles

3.                                                

Reason: Alternate interior angles are congruent

4.                                                              

Reason: Reflexive property

5.                                                  

Reason: SAS congruency theorem

6.                                                        

Reason: Corresponding Parts of Congruent triangles are Congruent (CPCTC)

7. ABCD is a parallelogram                                  

Reason: Parallelogram Side Theorem

Step-by-step explanation:

please mark me brainliest

6 0
1 year ago
Select the correct answer.
nordsb [41]

Answer:

A. The graph is a line that goes through the points (9,0) and (0,6).

Step-by-step explanation:

Given

4x + 6y = 36

Required

Select the true options

(a)\ (9,0)\ and\ (0,6)

This implies that"

(x_1,y_1)= (9,0)

(x_2,y_2)= (0,6)

So, we have: (x_1,y_1)= (9,0)

4x + 6y = 36

4 * 9 + 6 * 0 = 36 + 0 = 36

So, we have: (x_2,y_2)= (0,6)

4 * 0 + 6 * 6 = 0 + 36 = 36

<em>Hence (a) is true.</em>

3 0
2 years ago
Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II, what is the value of sin(theta)? NO LINKS!!!
vlada-n [284]
  • In second quadrant sin and cosec are positive

\\ \tt\hookrightarrow sin^2\theta=1-cos^2\theta

\\ \tt\hookrightarrow sin^2\theta=1-(\dfrac{-2\sqrt{5}}{5})^2

\\ \tt\hookrightarrow sin^2\theta=1-\dfrac{20}{25}

\\ \tt\hookrightarrow sin^2\theta=\dfrac{5}{25}

\\ \tt\hookrightarrow sin\theta=\dfrac{\sqrt{5}}{5}

\\ \tt\hookrightarrow sin\theta=\dfrac{1}{\sqrt{5}}

5 0
2 years ago
Use the formula to find the slope of the line that passes through these two points. Show your work.
Dafna1 [17]

Answer:

Solution given:

(x_1,y_1)=(1,2)

(x_2,y_2)=(7,7)

now

slope:\frac{y_2-y_1}{x_2-x_1}=\frac{7-2}{7-1}=\frac{5}{6}

Slope: 5/6

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12. When 64 is divided by x, the quotient is a negative
sergey [27]
J. -8 is the correct answer
8 0
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