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FrozenT [24]
3 years ago
15

What is the value of x?Enter your answer, as a decimal, in the box.​

Mathematics
2 answers:
Oksana_A [137]3 years ago
4 0

Answer:

42.9m

Step-by-step explanation:

The topic is on similar triangle

you are comparing triangle MNP with triangle MAB

side AB is similar to NP

side MA is similar to MN

side MB is similar to MP

now MA = MN - AN

              = 67.2 - 32

               = 35.2m

MA/MN = MB/MP

35.2/67.2 = x/81.9

cross multiply and solve

x = 42.9m

Ostrovityanka [42]3 years ago
4 0

Answer:

42.9 m

Step-by-step explanation:

AMB and NMP are similar figures

AM = 67.2 - 32 = 35.2

Similar figures have sides in the same ratio

AM/NM = MB/MP

35.2/67.2 = x/81.9

x = 35.2/67.2 × 81.9

x = 42.9 m

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Find the missing number in the pattern:
zhenek [66]

Answer:

The pattern is that they are multiplying by -3 every time. 81*-3 = -243

4 0
2 years ago
This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables
hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values ​​for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0
3 years ago
3 times 5 with a two on the top
jenyasd209 [6]
Ok so it could be
1. \frac{2}{3 times 5}
2. 3 timies \frac{2}{5}


ok if 1. then
\frac{2}{3 times 5}=\frac{2}{15}

if 2.  3 timies \frac{2}{5}= \frac{6}{5}



3 0
3 years ago
Kerry and Tya are sharing a pack of stickers. Each girl gets 11 stickers. Write and solve a division equation to find how many t
Shalnov [3]
Since each girl gets 11 sticker that means that there are 22 stickers in the pack.

11x2=22
4 0
3 years ago
QUESTION 5 of 10: You are considering selling your home. You consult with an agent who gives you the asking prices of five homes
san4es73 [151]

Answer: $169,500

Step-by-step explanation:

The mean simply means the average price of a set of a numbers that are given. For one t calculate the mean, one has to add the numbers that are given and then divide them by the amount of numbers.

I'm the case above, the numbers given are $165,000, $188,000, $175,000, and $150,000.

Mean = ($165,000 ,+ $188,000 +$175,000 + $150,000) ÷ 4

= $678,000/4

= $169,500

3 0
3 years ago
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