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Softa [21]
3 years ago
14

Need help asap in the middle of a test I really don’t understand this please help ASAP !?!

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Exam contents are prohibited here.

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Find the midpoint of the segment that has endpoints at<br> (a+b, a-b) and (a, b).
Hunter-Best [27]

Answer:

((2a+b)/2 , a/2)

Step-by-step explanation:

The midpoint is the mean/average of both the x and y values.

Our x values are a+b and a

Our y values are a-b and b

The midpoint x value is (a+b + a ) /2 = (2a + b)/2

The midpoint y value is (a-b + b) /2 = (a)/2

The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint

5 0
3 years ago
An ant travels at speed of 3 inches per second. How many feet will the ant travel in 2 hours?
GarryVolchara [31]

64,800 inches in 2 hours I think

6 0
3 years ago
Read 2 more answers
You are 5 feet tall and cast an 8-foot shadow. A lamppost nearby casts a shadow that is 20 feet. Which equation can you use to s
aleksandrvk [35]
I believe the answer is the first option. Tell me if i'm wrong. :)
3 0
3 years ago
Read 2 more answers
determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

The measure of these angles is 47°

7 0
1 year ago
Solve the linear system using multiplication Elimination.<br><br> 4х + Зу = 8<br> X - 2y = 13
motikmotik
X=5, y=-4
(5,-4)
do you need the work?
5 0
3 years ago
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