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4 years ago

Match the graph with its equation.

Mathematics

2 answers:

Vlada [557]4 years ago

8 0

The second choice is the answer based on my calculator

Assoli18 [71]4 years ago

5 0

Answer is x=-4 second choice

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An ESTIMATE of 39% of 120

malfutka [58]

ANSWER: 46.8

39% of 120

The word "of" means multiplied. So you will have to multiply 39% x 120

To do that, first step is to change the percent (39%) into a decimal

39% = 0.39 (You move the decimal twice to the left, not right)

There's an invisible decimal behind 9 so ALWAYS move it twice.

= 39(.)⇒ 0.39

Then your final step is to multiply

120 x 0.39

1 2 0

x 0 . 3 9 ← notice this decimal

_______ ∨

1 0 8 0 ∨

+ 3 6 0 0 ∨

_______ ∨

4 6 8 0 There's an invisible decimal before the 0. Move that decimal two times to the left. 4680(.)⇒ 46.8

4 0

3 years ago

Read 2 more answers

Express each ratio as a unit rate. Round to the nearest tenth, if necessary. 19 yards in 2.5 minutes

harkovskaia [24]

19 yards divided by 2.5 minutes.

=19/2.5

= 7.6 yards/minute

4 0

3 years ago

I just need help solving this problem. Also please don't put the answer into a file because I can't open them. It's also really

dem82 [27]

Answer:

Step-by-step explanation:

5 0

3 years ago

Polygon ABCD has the following vertices:

yKpoI14uk [10]

9514 1404 393

Answer:

(b) 38.5

Step-by-step explanation:

The polygon is a trapezoid with bases 4 and 7 and height 7. Its area is given by the formula ...

A = (1/2)(b1 +b2)h

A = (1/2)(4 +7)(7) = 77/2

A = 38.5 . . . . square units

8 0

3 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra

Nana76 [90]

The length of BC is $4 \sqrt{5}$ .

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

<u>Leg rule of geometric mean theorem:</u>

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

$\Rightarrow 16\times 5 = x\times x$

$\Rightarrow 80= x^2$

$\Rightarrow 16\times 5= x^2$

Taking square root on both sides.

$\Rightarrow \sqrt{16\times 5} = \sqrt{x^2}$

$\Rightarrow \sqrt{4^2\times 5} = \sqrt{x^2}$

square and square roots get canceled, we get

$\Rightarrow 4\sqrt{ 5} = x$

The length of BC is $4 \sqrt{5}$ .

7 0

3 years ago