Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?
2 answers:
Answer: 
Step-by-step explanation:
We know that the equation a line in point-slope form passing through points (a,b) and (c,d) is given by :-

Then , the equation a line in point-slope form passing through points C(3, –5) and D(6, 0) is given by :-

Hence, the equation of line CD in standard form : 
To answer the problem above, we can start with the formation of the point-slope form of a line. The slope is solved through,
m = (y2 - y1)/(x2 - x1)
m = (0 - -5)/ (6 - 3) = 5/3
The point - slope form of the equation of the line is,
y - y2 = m(x - x2)
Substituting the known data,
y - 0 = (5/3)(x - 6)
This simplifies into,
y = 5x/3 - 10
Thus, the standard form of the equation is,
5x - 3y = 30
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