Question

Alley has 10 kittens, and 4 puppies for sale. 4 of the kittens are girls and 6 are boys. 3 of the puppies are boys, and 1 is a girl. if alley offers a girl kitten for $250, a boy kitten for $230, a girl puppy for $349, and a boy puppy for $220, how much money will alley have if she sells all the puppies and kittens?

Answer 1

Boy kitten = $230
Girl kitten = $250
Girl puppy = $349
Boy puppy = $220
total money($)=4(250)+6(230)+3(220)+1(349)
total money($)=1,000+1,380+660+349
total money($)=2,380+660+349
total money($)=3,040+349
total money($)=$3,389
Alley will have $3,389 if she sells all the puppies and kittens.

Answer 2

Answer:to find the distance, use the equation:

distance = √(x1 - x2)^2 + (y1 - y2)^2

using that equation we can plug in our known values, and solve

√(1 - 2)^2 + ( 3 - (-4))^2

√(-1)^2 + (7)^2

√(1) + (49)

√50

to find the square root of 50, we have to rationalize. we can separate the 50 into √25 and √2, which would give us 5√2.

hope this helps!